2x+2-3x+3=x^2+2x+1-x^2-2x+6

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Solution for 2x+2-3x+3=x^2+2x+1-x^2-2x+6 equation: 



2x+2-3x+3=x^2+2x+1-x^2-2x+6

We move all terms to the left:

2x+2-3x+3-(x^2+2x+1-x^2-2x+6)=0

We add all the numbers together, and all the variables

-(x^2+2x+1-x^2-2x+6)-1x+5=0

We get rid of parentheses

-x^2+x^2-2x+2x-1x-1-6+5=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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